What is an equation of the line that passes through the point ( 1 , − 2 ) (1,−2) and is parallel to the line 6 x + y = 9 6x+y=9?

Answer:[tex]\boxed{y=-6x+4}\\[/tex]Step-by-step explanation:(a) Slope of parallel lineYour function is6x + y = 9        y = -6x + 9      Subtracted 6x from each side slope = -6The parallel line has slope = -6.(b) Equation for parallel lineThe point-slope formula for a straight line is    y – y₁ = m(x – x₁)x₁ = 1; y₁ = -2; m = -6   y – (-2) = -6(x - 1)    y + 2 = -6x + 6          y = -6x + 4The equation for the parallel line is  [tex]\boxed{y=-6x+4}\\[/tex]The graph is a straight line that passes through (1, -2) and has a slope of -6.